ELECTRICAL TECHNOLOGY AND INDUSTRIAL PRACTICE

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Saturday, August 29, 2020

August 29, 2020

CT burden calculation| How to calculate burden of Current Transformer

CT burden calculation. How to calculate Current Transformer burden






Before starting the discussion about CT or current transformer burden calculation we should know what is a burden!!!!!!

Burden is something which irritates?!!!! Actually burden is some additional load, which you need to bear.

Just like that the current transformer also need to drive some load which is called burden of CT or current transformer. Now what are the burdens?

For knowing that we need to understand what are the elements that are connected with the current Transformer. A protection class CT or current transformer has relays connected with it. And a metering class CT has mainly ammeter and multifunction meter connected with it. All this instruments has a small amount of power demand which is imposed on the current Transformer as burden of CT.

So basically sum of power demand of the instruments connected with the CT is called burden of CT. 

Now for outdoor switchyard what happened the current Transformer is installed on field. But the relay, MFM, ammeter etc are installed a certain distance away from the CT location, inside a panel. And this distance is connected via cable. So now there is a power loss in the cable, so that loss will also be included in CT burden calculation.

This is called lead burden. However lead burden js applicable mostly for CT installed at out door. Now,

Circuit diagram for Meter and relay connected with CT
Single line diagram of metering and protection
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Let us consider this picture. Here we can see a an Ammeter, a Tri vector meter and an MFM is connected in series with the current Transformer. So their VA rating will be added to the burden of CT.

Now from a typical catalogue of MFM and ammeter we have found that

Ammeter has a burden of around 0.9 VA.

MFM has burden of 0.5 VA (MFM  has two burden, one is on CT and the other one is on PT)

And TVM has a burden of say 0.6 VA.

So their total VA demand=2 VA.

Now we will calculate the lead burden. It is assumed that CTs are outdoor type, and they are connected with the meters with cable. Now we will find out the power loss in the cable.

CT burden calculation
Three line diagram of metering connection to CT
https://electricaltechnologyrishi.blogspot.com


So from the above diagram we can see that each CT is connected to the meter. So for completing the operating circuit(i.e. you can see that as per the ammeter selector switch position two leads will be connected between CT and meters, so we need to consider two cable) two nos. of cable runs are required, so we need to calculate the power loss for two runs. Generally 2.5 sq. mm Cu cables are used for such connection, so we will also consider the same.

2.5 sq mm Cu cable has resistance of 9.8 Ohm/ km.

Let's say the metering panels and CTs are 100 m away so we need to calculate resistance of 200 m cable. 200 is considered for to and fro run.

So total resistance will be 9.8*200/1000=1.96 Ohm

Say CT secondary rating is 1A, so total power loss=I^2*R=1*1*1.96=1.96 VA.

So, total burden will be 2+1.96=3.96 VA

So CT selected VA should be minimum 5 VA, however considerable margins are kept to burden selection.

Say the burden is selected as 15 VA.

Now let us see the condition for protection CT.

Relay connection to CT
Relay connection to the current Transformer
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From the diagram we can see the connection of the Relay with the CT. Here also for calculating the lead burden our consideration will similar as that for protection.

Since the relay, meter all are housed in a same panel so lead resistance will be same for both the case.

Numerical relay has burden of around 0.2 VA. So total burden for protection CT is 1.96+0.2= 2.16 VA.

Let us select 15 VA CT. Now Selection of such higher value of CT burden will give us another advantage. We will see that.

Suppose our selected CT is 5P20 class CT, i.e. its Accuracy limit factor is 20. Now if the VA is higher the actual ALF will increase.

The corrected or actual accuracy limit factor or ALF can be found as following

ALF'=ALF*(Pi+Pn)/(Pi+Pr)

Where 

ALF'= The actual accuracy limit factor

ALF= Rated accuracy limit factor

Pi=CT internal I^2*R loss

Pn=Selected CT burden

Pr=Actual burden on CT.

Out CT is 1A secondary rated, and CT resistance shall be maximum 5 ohm (Rct<=5 ohm).

So, Pi=5VA

Pn= say 15

Pr= 2.16 VA (burden of numerical relay and cable)

And the CT is a 5P20 CT so ALF=20.

So, ALF'= 55.86

So our 5P20 CT will act like 5P56.

Its accuracy limit factor will increase. So thus the actual ALF of CT increases with higher burden selection.


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Thank you......







Tuesday, August 18, 2020

August 18, 2020

Why AC is preferred over DC

 Why is Alternating current or AC is preferred over Direct Current or DC


In our early days the main power distribution used to be carried out by DC or direct current. The direct current distribution was developed by Thomas Edition. 

Later on one of his employee Nicolas Tesla developed alternating current or AC. Gradually AC or alternating current over took the direct current distribution or DC distribution. 

Now question arises that why direct current or DC usage got reduced and Alternating Current or AC gained popularity. There are many advantages of AC power over DC. 

In this article we will be discussing about those advantages.

The first reason of Alternating Current or AC having such application is

1. The induction phenomenon.

Due to this induction the Transformer is introduced which can easily change the voltage level. Changes voltage is very much essential for a successful Power system. Why??? Let's see......

We know that Power=Voltage×Current. Now if we want to transfer a huge amount of power and we don't increase the voltage, the current will increase. High value of current will cause high power loss, voltage drop, heating, heavy conductor cross section. Overall causing poor power system. Hence we need to increase the voltage for sending the power. Again at the receiving end we need to reduce back the voltage at our desired utilisation level. So frequent changes in voltage is desired for a healthy power system. Now this process becomes very easy with transformer and Alternating Current or AC.

But changing in voltage with DC is very difficult as it needs power electronics device.

So that is very important reason we are using AC over DC.

2. Circuit Breaking Ease.

Alternating Current or AC changes its magnitude with respect to time i.e. it starts from zero, goes to its maximum value, then come backs to zero, then goes to negetive magnitude (i.e. changing the direction of flow) and again goes to zero. So for completing a cycle an AC wave crosses three no zeros. At those point of the circuit has no voltage, and therefore no current or arc. So the insulation at the break point can be easily established at the point zero crossing, making the circuit breaker to operate with less difficulty.

Why ac is preferred over DC
AC signal with zero crossing
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But in direct current or DC breaker as DC has no zero crossing it is difficult to extinguish the arc, and re establish the insulation.

Whys is ac prefered over DC
DC signal with no zero crossing
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So for easy circuit Breaking and fault isolation AC is preferred over DC.

3. Low Cost of Metering instrument for AC than DC.

In AC system we have instrument transformer which reduces the voltage and current at lower level suitable for measurements. But in direct current or DC system there is no such Instrument transformer. So other type of sensors are required for measurements.

Also for AC measurement Moving Iron instruments are used which is less expensive that PMMC instrument that are used for DC.

To over come these difficulties in HVDC often the circuit Breaking and measurement is made at AC side.

So these are the three major reason for which AC power is preferred over DC power.

Apart from these there are also may factors like 

4. DC  equipment like motor, generators are bulky in size due to huge copper winding, competitively AC machines are robust in size.

5. DC machines are doubly excited machine where as AC machines are singly excited(induction motor)

6. No need to replace Carbon brushes as that required in DC machine.

7. Due to absense of Brushes there is no commutation problem in AC machines, no spark.


So these are the main reason why we shifted to Alternating Current system from direct current supply system.


Hope you have enjoyed this article.

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